Objective In this challenge, we're going to use loops to help us do some simple math. Task Given an integer, , print its first multiples. Each multiple (where ) should be printed on a new line in the form: N x i = result . Input Format A single integer, . Constraints Output Format Print lines of output; each line (where ) contains the of in the form: N x i = result . Sample Input 2 Sample Output 2 x 1 = 2 2 x 2 = 4 2 x 3 = 6 2 x 4 = 8 2 x 5 = 10 2 x 6 = 12 2 x 7 = 14 2 x 8 = 16 2 x 9 = 18 2 x 10 = 20 Explanation: Here, we just need to use for loops to achieve the result Solution : import java.io.* ; import java.math.* ; import java.security.* ; import java.text.* ; import java.util.* ; import java.util.concurrent.* ; import java.util.regex.* ; public class Solution { public static void main ( String [] args ) throws IOException { BufferedReader bufferedReader = new BufferedReader ( new InputStreamReader ( Syste
Given an array, print the Next Greater Element (NGE) for every element. The Next greater Element for an element x is the first greater element on the right side of x in the array. Elements for which no greater element exist, consider the next greater element as -1. eg: input=[11,4,3,2,10,12] ouput : 12 ,10,10,10,12,-1 EXPLANATION: Find the first next greater element for each element. If the element have no greater element replace the element with -1 APPROACH: Using Stack. Logic: Create one stack for storing the index of the array elements using for loop iterate over each element. compare variable to store the next greater element If the element you are iterating is lesser than the compare element, then push into the stack. If the element you are iterating is greater than the compare element pop the index from stack then replace the index position of output array with the greater element. Repeat this while loop until it is not greater than compare