Java Loops | HackerRank solutions -codewithyasar

 Objective

In this challenge, we're going to use loops to help us do some simple math.

Task
Given an integer, , print its first  multiples. Each multiple  (where ) should be printed on a new line in the form: N x i = result.

Input Format

A single integer, .

Constraints

Output Format

Print  lines of output; each line  (where ) contains the  of  in the form:
N x i = result.

Sample Input

2

Sample Output

2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20

Explanation:

        Here, we just need to use for loops to achieve the result

Solution :

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;



public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

        int N = Integer.parseInt(bufferedReader.readLine().trim());
        int result;
        bufferedReader.close();
        for (int i=1; i<=10; i++) {
            result=N*i;
            System.out.printf("%d x %d = %d%n",N,i,result);
        }
       
    }
}

//%n - will be responsible for printing in next line