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Java Loops | HackerRank solutions -codewithyasar

  Objective In this challenge, we're going to use loops to help us do some simple math. Task Given an integer,  , print its first   multiples. Each multiple   (where  ) should be printed on a new line in the form:  N x i = result . Input Format A single integer,  . Constraints Output Format Print   lines of output; each line   (where  ) contains the   of   in the form: N x i = result . Sample Input 2 Sample Output 2 x 1 = 2 2 x 2 = 4 2 x 3 = 6 2 x 4 = 8 2 x 5 = 10 2 x 6 = 12 2 x 7 = 14 2 x 8 = 16 2 x 9 = 18 2 x 10 = 20 Explanation:           Here, we just need to use for loops to achieve the result Solution : import java.io.* ; import java.math.* ; import java.security.* ; import java.text.* ; import java.util.* ; import java.util.concurrent.* ; import java.util.regex.* ; public class Solution { public static void main ( String [] args ) t...
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Least Number

Least Number

You are given an array of positive numbers, find the minimum number which is not present in the list, which also cannot be represented as a combination of numbers in the array.


Input Format : The first line of input has one single integer input N The second line of input has N spaced integers

Input Constraints : 1<=N<=10^3 1<=a[i]<=10^3

Output Format : One single integer output

Sample Input :4 1 2 5 6


Sample Output :

4

Logic:
  • To find first least number.we need to sort the array.
  • And we need to identify the least number is not in combination of elements
  • so,add the elements and compare to find first least number which is not in list and combination.
Code logic:
  1. Get input from the user.
  2. Get input array
  3. Sort the given array
  4. Intialize as ans=1
  5. for I in arr:
  6. check ans >=i:
  7. if greater add with I
  8. else:break
Program:

n=int(input("No.of.elements"))
arr=list(map(int,input().split()))
arr.sort()
ans=1
for i in arr:
if ans>=i:
ans+=i
else:
break
print(ans)
view raw LeastNumber.py hosted with ❤ by GitHub
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